HCF and LCM Quiz - ICSE Class 6 Mathematics
Free practice quiz: HCF and LCM (ICSE Class 6 Mathematics). 56 multiple-choice questions with answers and explanations. Play online, no sign-up needed.
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Find the Highest Common Factor (HCF) of 24, 36, and 48.
- 6
- 12
- 24
- 36
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Answer: B. 12
To find the HCF, we can list the factors of each number: Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24 Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 The common factors are 1, 2, 3, 4, 6, and 12. The highest common factor is 12.
Find the largest 4-digit number exactly divisible by 12, 18, and 24.
- 9972
- 9936
- 9864
- 9900
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Answer: B. 9936
First, find the LCM of 12, 18, and 24. LCM(12, 18, 24) = 72. Now, find the largest 4-digit number, which is 9999. Divide 9999 by 72: 9999 / 72 = 138 with a remainder of 63. To find the largest multiple of 72 less than or equal to 9999, subtract the remainder from 9999: 9999 - 63 = 9936. Thus, 9936 is the largest 4-digit number divisible by 12, 18, and 24.
If the HCF of two numbers is 15 and their LCM is 135. If one number is 45, what is the other number?
- 15
- 30
- 45
- 35
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Answer: C. 45
Using the property: Product of two numbers = HCF x LCM. Let the other number be 'x'. 45 * x = 15 * 135 45x = 2025 x = 2025 / 45 x = 45.
Find the largest number that divides 180, 252, and 324 exactly.
- 12
- 18
- 36
- 3
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Answer: C. 36
We need to find the HCF of 180, 252, and 324. Prime factorization: 180 = 2^2 x 3^2 x 5 252 = 2^2 x 3^2 x 7 324 = 2^2 x 3^4 The common prime factors with the lowest powers are 2^2 and 3^2. HCF = 2^2 x 3^2 = 4 x 9 = 36.
The product of two numbers is 2000 and their HCF is 10. What is their LCM?
- 200
- 100
- 20
- 1000
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Answer: A. 200
Using the property: Product of two numbers = HCF x LCM. Given: Product = 2000, HCF = 10. So, 2000 = 10 x LCM. LCM = 2000 / 10 = 200.