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Statistics – Measures of Dispersion (Range, Quartile, Standard, Mean Deviation, Coefficient of Variation) Quiz - ICSE Class 11 Economics

Free practice quiz: Statistics – Measures of Dispersion (Range, Quartile, Standard, Mean Deviation, Coefficient of Variation) (ICSE Class 11 Economics). 79 multiple-choice questions with answers and explanations. Play online, no sign-up needed.

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Sample questions

  1. For a dataset with values {2, 5, 8, 10, 15}, calculate the range.

    1. 13
    2. 10
    3. 15
    4. 8
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    Answer: A. 13

    The range is the difference between the maximum and minimum values in a dataset. Here, the maximum value is 15 and the minimum value is 2. Therefore, Range = 15 - 2 = 13.

  2. If the range of a dataset is 30 and the minimum value is 5, what is the maximum value?

    1. 35
    2. 25
    3. 30
    4. 15
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    Answer: A. 35

    The range is the difference between the maximum and minimum values. Range = Maximum Value - Minimum Value. Given Range = 30 and Minimum Value = 5, then 30 = Maximum Value - 5. Therefore, Maximum Value = 30 + 5 = 35.

  3. Which of the following measures of dispersion is not affected by the addition of an outlier to the dataset?

    1. Range
    2. Standard Deviation
    3. Interquartile Range
    4. Mean Deviation
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    Answer: C. Interquartile Range

    The Interquartile Range (IQR) is calculated from the first and third quartiles. Quartiles divide the data into four equal parts, making the IQR resistant to extreme values (outliers). Range, Standard Deviation, and Mean Deviation are all sensitive to outliers as they consider all data points or extreme values directly.

  4. If a dataset has a mean of 50 and a standard deviation of 0, what are the values in the dataset?

    1. All values are 50.
    2. All values are 0.
    3. The values are spread around 0.
    4. The values are spread around 50.
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    Answer: A. All values are 50.

    A standard deviation of 0 indicates that there is no dispersion in the data. This means all data points are identical. If the mean is 50 and there is no dispersion, then all data points must be exactly 50.

  5. For the dataset {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, calculate the Mean Deviation from the Mean.

    1. 2.5
    2. 3
    3. 1.5
    4. 2
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    Answer: A. 2.5

    First, calculate the mean: (1+2+3+4+5+6+7+8+9+10)/10 = 55/10 = 5.5. Then calculate the absolute deviations from the mean: |1-5.5|=4.5, |2-5.5|=3.5, |3-5.5|=2.5, |4-5.5|=1.5, |5-5.5|=0.5, |6-5.5|=0.5, |7-5.5|=1.5, |8-5.5|=2.5, |9-5.5|=3.5, |10-5.5|=4.5. The sum of absolute deviations is 4.5+3.5+2.5+1.5+0.5+0.5+1.5+2.5+3.5+4.5 = 25. Mean Deviation = 25 / 10 = 2.5.

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