Force Quiz - ICSE Class 10 Physics
Free practice quiz: Force (ICSE Class 10 Physics). 51 multiple-choice questions with answers and explanations. Play online, no sign-up needed.
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A body of mass 10 kg is moving with a uniform velocity of 5 m/s on a frictionless horizontal surface. If a force of 50 N is applied in the opposite direction of motion, what will be the acceleration of the body?
- 5 m/s²
- -5 m/s²
- 10 m/s²
- -10 m/s²
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Answer: B. -5 m/s²
Initially, the body is moving with a uniform velocity, meaning its acceleration is zero. When a force is applied in the opposite direction of motion, it will cause deceleration. Using Newton's second law, F = ma, where F = -50 N (since it's opposite to motion) and m = 10 kg, we get a = F/m = -50 N / 10 kg = -5 m/s².
A ball of mass 0.5 kg is dropped from a height of 10 m. Ignoring air resistance, what is the velocity of the ball just before it hits the ground? (g = 10 m/s²)
- 10 m/s
- 14.14 m/s
- 20 m/s
- 100 m/s
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Answer: B. 14.14 m/s
We can use the kinematic equation v² = u² + 2as, where u is the initial velocity (0 m/s since it's dropped), a is the acceleration due to gravity (g = 10 m/s²), and s is the distance (height = 10 m). So, v² = 0² + 2 * 10 m/s² * 10 m = 200 m²/s². Therefore, v = sqrt(200) ≈ 14.14 m/s.
If the mass of an object is doubled and the acceleration remains the same, the applied force will be:
- Halved
- Doubled
- Quadrupled
- Unchanged
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Answer: B. Doubled
According to Newton's second law (F = ma), if mass (m) is doubled and acceleration (a) remains constant, then the force (F) must also be doubled to maintain the equality.
A car accelerates from rest at 2 m/s² for 5 seconds. What is the final velocity of the car?
- 2.5 m/s
- 5 m/s
- 10 m/s
- 20 m/s
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Answer: C. 10 m/s
Using the kinematic equation v = u + at, where u (initial velocity) = 0 m/s (since it starts from rest), a = 2 m/s², and t = 5 s. Therefore, v = 0 + (2 m/s²)(5 s) = 10 m/s.
A shot-putter throws a shot. What provides the force to accelerate the shot?
- The gravitational force on the shot.
- The normal force from the ground.
- The force exerted by the shot-putter's muscles.
- Air resistance.
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Answer: C. The force exerted by the shot-putter's muscles.
The shot-putter applies a muscular force to the shot, causing it to accelerate. Gravity and air resistance are also acting on the shot, but the primary force responsible for its acceleration is the force from the thrower.