Motion in 2D Quiz - CBSE Class 12 Physics

Free practice quiz: Motion in 2D (CBSE Class 12 Physics). 20 multiple-choice questions with answers and explanations. Play online, no sign-up needed.

Sample questions

1. What is the resultant of two vectors of equal magnitude acting at right angles to each other?

   1. Equal to the sum of the magnitudes
   2. Equal to the difference of the magnitudes
   3. Equal to the square root of the sum of the squares of the magnitudes
   4. Zero
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   Answer: C. Equal to the square root of the sum of the squares of the magnitudes

   When two vectors of equal magnitude act at right angles, the resultant vector can be found using the Pythagorean theorem. If the magnitude of each vector is 'A', then the resultant R = √(A² + A²) = A√2.

2. A car moves in a circular track with constant speed. What can be said about its velocity?

   1. It is constant
   2. It is changing
   3. It is zero
   4. It is equal to the acceleration
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   Answer: B. It is changing

   Even though the speed of the car is constant, its direction is continuously changing as it moves along the circular path. Therefore, the velocity, which includes direction, is changing.

3. An object is projected upward at a velocity of 15 m/s. What will be its maximum height? (g = 9.8 m/s²)

   1. 11.47 m
   2. 22.5 m
   3. 25.77 m
   4. 15.3 m
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   Answer: A. 11.47 m

   The maximum height can be found using the equation h = (v^2) / (2g). Here, h = (15 m/s)² / (2 * 9.8 m/s²) = 225 / 19.6 = 11.47 m.

4. A ball thrown upward will reach maximum height and then fall back. What is the vertical speed at the maximum height?

   1. Negative
   2. Zero
   3. Positive
   4. Depends on the initial speed
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   Answer: B. Zero

   At maximum height, the vertical component of the speed becomes zero before the object starts to descend due to gravity.

5. A ball is dropped from a height. After 2 seconds, what will be its speed? (g = 9.8 m/s²)

   1. 19.6 m/s
   2. 9.8 m/s
   3. 0 m/s
   4. 39.2 m/s
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   Answer: A. 19.6 m/s

   The speed of the ball after falling for a time t can be calculated using v = g*t. Here, v = 9.8 m/s² * 2 s = 19.6 m/s.

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