Introduction to Probability Quiz - CBSE Class 11 Mathematics
Free practice quiz: Introduction to Probability (CBSE Class 11 Mathematics). 17 multiple-choice questions with answers and explanations. Play online, no sign-up needed.
Play all 17 questions freeSample questions
What is the probability of getting a head when tossing a fair coin?
- 0
- 1/2
- 1/4
- 1
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Answer: B. 1/2
A fair coin has two equally likely outcomes: heads or tails. The probability of getting heads is the number of favorable outcomes (1) divided by the total number of possible outcomes (2).
A card is drawn from a standard deck of 52 cards. What is the probability that the card is a king?
- 1/13
- 1/4
- 4/13
- 1/52
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Answer: A. 1/13
There are 4 kings in a standard deck of 52 cards. The probability of drawing a king is the number of kings (4) divided by the total number of cards (52), which simplifies to 1/13.
A box contains 10 light bulbs, of which 3 are defective. Two bulbs are selected at random without replacement. What is the probability that both bulbs are defective?
- 3/30
- 3/10
- 1/15
- 1/10
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Answer: C. 1/15
Probability of the first bulb being defective is 3/10. After selecting one defective bulb, there are 2 defective bulbs left out of 9 total bulbs. The probability of the second bulb being defective is 2/9. The probability of both events happening is (3/10) * (2/9) = 6/90 = 1/15.
A committee of 3 people is to be selected from a group of 5 men and 4 women. What is the probability that the committee will consist of 2 men and 1 woman?
- (5C2 * 4C1) / 9C3
- (5C2 + 4C1) / 9C3
- (5C2 * 4C1) / (5P2 * 4P1)
- (5P2 * 4P1) / 9P3
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Answer: A. (5C2 * 4C1) / 9C3
We need to choose 2 men from 5 and 1 woman from 4. The number of ways to do this is 5C2 * 4C1. The total number of ways to choose a committee of 3 from 9 people is 9C3. The probability is (5C2 * 4C1) / 9C3.
A box contains 5 red balls and 3 blue balls. Two balls are drawn at random without replacement. What is the probability that the first ball is red and the second ball is blue?
- (5/8) * (3/7)
- (5/8) * (3/8)
- (5/8) + (3/7)
- (5/8) + (3/8)
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Answer: A. (5/8) * (3/7)
The probability of drawing a red ball first is 5/8. After drawing one red ball, there are 3 blue balls and 4 red balls remaining, for a total of 7 balls. The probability of drawing a blue ball second is 3/7. The probability of both events occurring is (5/8) * (3/7).